16x^2-22x+5=2x

Solution for 16x^2-22x+5=2x equation:

16x^2-22x+5=2x

We move all terms to the left:

16x^2-22x+5-(2x)=0

We add all the numbers together, and all the variables

16x^2-24x+5=0

a = 16; b = -24; c = +5;
Δ = b2-4ac
Δ = -242-4·16·5
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16}{2*16}=\frac{8}{32}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16}{2*16}=\frac{40}{32}
=1+1/4
$